/14 Subnet Mask ReferenceIPv4

Four tidy /16s under one summary: that is a /14, masked <code>255.252.0.0</code>, with 262,142 usable addresses. Long-lived institutions often hold several adjacent /16s that summarize into exactly this shape.

The /14 subnet mask is 255.252.0.0, equivalent to 0.3.255.255 as a wildcard. A /14 block contains 262,144 IP addresses (262,142 usable hosts).

/14 facts at a glance

Subnet mask
255.252.0.0
Wildcard mask
0.3.255.255
Binary mask
11111111.11111100.00000000.00000000
Total addresses
262,144
Usable hosts
262,142 (excludes network & broadcast)
Block size
262,144 addresses (218)
Typical role
Large enterprise and carrier aggregation

Example /14 networks

Three consecutive /14 blocks, starting at the /14 boundary that contains 198.51.100.0:

NetworkUsable rangeUsable hosts
198.48.0.0/14 198.48.0.1 – 198.51.255.254 262,142
198.52.0.0/14 198.52.0.1 – 198.55.255.254 262,142
198.56.0.0/14 198.56.0.1 – 198.59.255.254 262,142

How to calculate a /14 mask

A /14 mask sets the first 14 bits of a 32-bit number to 1 and leaves the remaining 18 bits as 0. In binary that reads 11111111.11111100.00000000.00000000, which converts to dotted decimal 255.252.0.0. Each block covers a contiguous run of 218 = 262,144 addresses, and every block starts at a multiple of that size. The wildcard simply flips every bit, giving 0.3.255.255.

Where /14 is used

Example: <code>140.80.0.0/14</code> covers 140.80.0.0 through 140.83.255.255. Alignment check: the second octet of any /14 must be a multiple of four.

Frequently asked questions

What is the subnet mask for /14?

<code>255.252.0.0</code>, wildcard <code>0.3.255.255</code>, which fixes six bits of the second octet.

How many hosts are in a /14?

262,142 usable of 262,144 total addresses.

How many /16s combine into a /14?

Four, provided they are consecutive and the starting second octet is divisible by four.

Open the /14 block in the subnet calculator

Get the /14 wildcard mask →

Related prefixes

/13/15/24/26/28/30