/6 Subnet Mask ReferenceIPv4

Four /8 networks bundled under mask <code>252.0.0.0</code>: that is a /6, holding 67,108,864 addresses. It dwarfs any conceivable deployment, so the prefix survives mainly in textbooks and route-aggregation worksheets.

The /6 subnet mask is 252.0.0.0, equivalent to 3.255.255.255 as a wildcard. A /6 block contains 67,108,864 IP addresses (67,108,862 usable hosts).

/6 facts at a glance

Subnet mask
252.0.0.0
Wildcard mask
3.255.255.255
Binary mask
11111100.00000000.00000000.00000000
Total addresses
67,108,864
Usable hosts
67,108,862 (excludes network & broadcast)
Block size
67,108,864 addresses (226)
Typical role
Aggregation and supernetting

Example /6 networks

A /6 spans a large share of the address space, so one aligned example says it all.

NetworkUsable rangeUsable hosts
196.0.0.0/6 196.0.0.1 – 199.255.255.254 67,108,862

How to calculate a /6 mask

A /6 mask sets the first 6 bits of a 32-bit number to 1 and leaves the remaining 26 bits as 0. In binary that reads 11111100.00000000.00000000.00000000, which converts to dotted decimal 252.0.0.0. Each block covers a contiguous run of 226 = 67,108,864 addresses, and every block starts at a multiple of that size. The wildcard simply flips every bit, giving 3.255.255.255.

Where /6 is used

Alignment rule: a /6 network must start on a first octet divisible by four, such as 64, 68, 124, or 220.

Frequently asked questions

What is the subnet mask for /6?

<code>252.0.0.0</code>, with wildcard <code>3.255.255.255</code>. Six leading one-bits leave 26 host bits.

How many addresses are in a /6?

67,108,864 total; 67,108,862 usable after the standard two-address deduction.

Why would a block this large never be deployed?

Even the largest carriers control only a handful of /8s, and no routing domain approaches tens of millions of hosts. The prefix exists for aggregation math.

Open the /6 block in the subnet calculator

Get the /6 wildcard mask →

Related prefixes

/5/7/24/26/28/30